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You need to work with a solution of hydrochloric acid in a concentration of 3 moles/L. However, you only have a 2L solution of hydrochloric acid with a concentration of 6 moles per liter. How much water do you need to add to your initial solution to have the molarity of 3 moles/L you are required? L (HINT: notice it is not asking for the final volume.)

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SvetkaChem

Answer:

2L of water

Explanation:

M1V1 = M2V2

M1= 6 mol/L

V1=2L

M2= 3 mol/L

V2 =? volume of 3 mol/L solution

6mol/L*2L = 3 mol/L*V2

V2 = 12/3 = 4 L

We have 2 L solution, we have to get 4 L solution.

So, we need to add (4-2)=2 L of water.

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