Which shows how to find the value of this expression when x = negative 2 and y = 5?

(3 x cubed y Superscript negative 2 Baseline) squared
StartFraction 3 squared (negative 2) Superscript 6 Baseline Over 5 Superscript 4 EndFraction
StartFraction 3 (negative 2) Superscript 6 Baseline Over 5 Superscript 4 EndFraction
StartFraction 3 squared (5 Superscript 6 Baseline) Over (negative 2) Superscript negative 4 Baseline EndFraction
StartFraction 3 Over (2) Superscript 6 Baseline 5 Superscript 4 Baseline EndFraction

Respuesta :

Answer:

(A) [tex]\dfrac{3^2(-2)^6}{5^{4}}[/tex]

Step-by-step explanation:

Given the expression;

[tex](3x^3y^{-2})^2[/tex]

When x=-2, y=5

We have:

[tex](3(-2)^3(5)^{-2})^2=3^2\cdot(-2)^6\cdot5^{-4}\\=\dfrac{3^2\cdot(-2)^6}{5^{4}}[/tex]

The correct option is A

StartFraction 3 squared (negative 2) Superscript 6 Baseline Over 5 Superscript 4 EndFraction

Answer:

A

Step-by-step explanation:

I took the test on edge