Answer:
F = 0.112 N
Explanation:
To find the magnitude of magnetic force on the wire, you use the following formula:
[tex]|\vec{F}|=|i\vec{L}\ X\ \vec{B}|=iLBsin\theta[/tex] (1)
L: length of the wire = 200cm = 0.2m
i: current in the wire = 30 A
B: magnitude of the magnetic field = 0.055 T
θ: angle between the directions of L and B = 20°
You replace the values of L, i, B and θ in the equation (1):
[tex]|\vec{F}|=(30A)(0.2m)(0.055T)sin(20\°)=0.112N[/tex]
hence, the magnetic force on teh wire is 0.112N
