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An orange is shot up into the air with a catapult. The function h given by

h(t) = 15 + 60t – 16t2 models the orange's height, in feet, 1 seconds after it was

launched.

Question 5 What is the initial speed at which the orange is shot in the air?

Respuesta :

Answer:

Velocity = 59 feet/second

Step-by-step explanation:

h(t) = 15 + 60t – 16t2

Time t = 1 second

Let's substitute time into the equation to get the distance

h(t) = 15+60(1)-16(1)²

h(t) = 15 + 60 - 16

h(t) = 59 feet

Speed or velocity = distance/time

Distance = 59 feet

Time = 1 second

Velocity = 59/1

Velocity = 59 feet/s

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