Answer:
[tex]a_{10}=124[/tex]
Step-by-step explanation:
In an arithmetic sequence, we are given that:
[tex]a_{17}=82\\d=-6[/tex]
The nth term of an arithmetic sequence, [tex]a_n=a+(n-1)d[/tex]
When n=17, [tex]a_{17}=82,d=-6[/tex], we have:
[tex]a_{17}=a+(17-1)(-6)[/tex]
82=a+(16)(-6)
82=a-96
a=82+96
a=178
Therefore, the 10th term of the sequence
[tex]a_{10}=178+(10-1)(-6)\\=178+9(-6)\\=178-54\\a_{10}=124[/tex]