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1) In 1.31 g of a chloride of titanium, there is 0.528 g of titanium. What is the empirical formula of this titanium chloride?

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Answer:

TiCl2

Explanation:

Mass of the chloride of titanium= 1.31 g

Mass of titanium= 0.528 g

Therefore mass of chlorine = 1.31-0.528 = 0.782 g

To determine the empirical formulae of the titanium chloride, divide the mass of each element by its relative atomic mass and divide through by the lowest ratio.

Ti- 0.528/48 = 0.011, Cl- 0.782/35.5 = 0.022

Ti- 0.011/0.011 , Cl- 0.022/0.011

Ti- 1, Cl-2

Hence the required empirical formula is TiCl2