Answer:
[tex]M=0.822M[/tex]
Explanation:
Hello,
In this case, given the mathematical definition of molar concentration as the moles of solute divided by the liters of solution:
[tex]M=\frac{n}{V}[/tex]
We can easily compute it by firstly computing the moles of sugar by using its molar mass:
[tex]n=73.1g*\frac{1mol}{342.30g} =0.214mol[/tex]
After that, we compute the concentration by realizing 259.8 mL equals 0.2598 L:
[tex]M=\frac{0.214mol}{0.2598L}\\ \\M=0.822mol/L[/tex]
Or just:
[tex]M=0.822M[/tex]
Considering molar units as mol/L
Best regards.
The molar concentration of the solution is 0.82 M
We'll begin by by converting 259.8 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
259.8 mL = 259.8 / 1000
Thus, 259.8 mL is equivalent to 0.2598 L.
Next, we shall determine the number of mole of the sugar. This can be obtained as follow:
Molar mass of sugar = 342.30 g/mol.
Mass of sugar = 73.1 g
Mole = mass / molar
Mole = 73.1 / 342.30
Finally, we shall determine the molar concentration of the sugar. This can be obtained as follow:
Mole of sugar = 0.214 mole
Volume = 0.2598 L
Molarity = 0.214 / 0.2598
Therefore, the molar concentration of the solution is 0.82 M
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