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The vertical component of a velocity vector points up and has a magnitude of 20, ms'. The velocity vector Itself makes an angle of 25' with the horizontal. Find the magnitude of the velocity vector.

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Answer:

Kindly check explanation

Explanation:

Given the following :

Vertical component has Magnitude = 20m/s

Angle made with the horizontal (θ) = 25°

Vy = Vsinθ = 20sin25

Vy = 20 × 0.4226182 = 8.4523652 m/s

Horizontal component :

Vx = Vcosθ = 20 × cos25

Vx = 20 × 0.9063077 = 18.126155 m/s

Hence, magnitude :

V = sqrt(Vx² + Vy²)

V = sqrt(8.4523652² + 18.126155²)

V = sqrt (399.99999)

V = 20m/s

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