08-11-2014
Mathematics

contestada

8) solve for o≤x≤360
a) sin²x-sinx=0

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08-11-2014

[tex]sin^2x-sinx=0\\\\sinx(sinx-1)=0\iff sinx=0\ or\ sinx-1=0\\\\sinx=0\iff x=0^o\ or\ x=180^o\ or\ x=360^o\\\\sinx-1=0\\sinx=1\iff x=90^o\\\\Answer:\boxed{x\in\{0^o;\ 90^o;\ 180^o;\ 360^o\}}[/tex]

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