The perimeter of PRST is 10 more than 5(RS). If PR=26, find RS.

Answer:
RS = 14
Step-by-step explanation:
Perimeter = 26 + 26 + PT + RS
We know that PT and RS are equal to each other so I changed the equation to 26 + 26 + x + x = 10 + 5x and then I got x by itself and the integer on one side 42 = 3x, so 14 = x
The value of RS will be 14 for the given parallelogram.
A basic quadrilateral with two sets of parallel sides is known as a parallelogram.
A parallelogram's facing or opposing sides are of equal length, and its opposing angles are of similar size.
There are 4 types of parallelograms, including 3 special types. The four types are parallelograms, squares, rectangles, and rhombuses.
Given the parallelogram where TS ║ PR and both are equal
Line TP ║ SR so it means TP = SR
Let's say
TP = SR = x
Now,
The perimeter of a parallelogram is 10 more than 5(RS)
So,
PT + TS + SR + RP = 5(RS) + 10
Now since TP = RS = x
So,
x + TS + x + RP = 5x + 10
5x - 2x = TS + RP - 10
x = (TS + RP - 10)/3
Now,
TS = RP = 26
So,
x = (26 + 26 - 10 )/3
x = 42/3
x = 14
Hence "The value of RS will be 14 for the given parallelogram".
Learn more about parallelograms here
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