The time when the ball hit the ground, which is thrown from a height of 70 meters with an initial downward velocity of 10 m/s is 2.87.
A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.
The standard form of the quadratic equation is,
[tex]ax^2+bx+c=0[/tex]
Here,(a,b, c) is the real numbers and (x) is the variable. To solve the equation for x, use the following formula,
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
The ball's height h (in meters) after t seconds is given by the following.
[tex]h=70-10t-5t^2[/tex]
The ball is thrown from a height of 70 meters with an initial downward velocity of 10 m/s. In this case,
The time when the ball hit the ground has to be find out. The value of the height when it hit the group is zero. Put the value of h=0 in the above equation,
[tex]h=70-10t-5t^2\\0=70-10t-5t^2\\5t^2+10t-70=0\\5t^2+10t-70=0\\[/tex]
Solve the quadratic equation using the following formula,
[tex]t=\dfrac{-10\pm \sqrt{10^2-4(10)(-70)}}{2\times5}\\t=-4.87, t=2.87[/tex]
Consider positive value. Thus, the time when the ball hit the ground, which is thrown from a height of 70 meters with an initial downward velocity of 10 m/s is 2.87.
Learn more about the quadratic equation here;
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