Respuesta :

Answer:

(4x^4  + 3y) * (16x^8  - 12x^4 y + 9y^2)

Step-by-step explanation:

rewrite 64x^12 as  (4x^4)^3

(4x^4)^3 + 27y^3

rewrite 27y^3 as (3y)^3

a^3+b^3=(a+b)(a^2 - ab + b^2)

(4x^4 + 3y) ((4x^4)^2 - (4x^4 * (3y) + (3y)^2)

[tex]\\ \rm\Rrightarrow 64x^{12}+27y^3[/tex]

[tex]\\ \rm\Rrightarrow 4^3x^3x^6x^3+3^3y^3[/tex]

[tex]\\ \rm\Rrightarrow (4xxxx)^3+(3y)^3[/tex]

[tex]\\ \rm\Rrightarrow (4x^3)^3+(3y)^3[/tex]

  • a^3+b^3=(a+b)(a^2+ab+b^2)

[tex]\\ \rm\Rrightarrow (4x^3+3y)(16x^6+12x^3y+9y^2)[/tex]

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