An acorn is falling from 13 feet in the air. If it descends 4.8 feet every second, write and solve an equation to determine how long it will take for the acorn to be 1 foot above the ground. please put the equation and answer please.

Respuesta :

Using a linear function, it is found that:

  • The equation that has to be solved is: [tex]-4.8t + 13 = 1[/tex]
  • It takes 2.5 seconds for the acorn to be 1 foot above the ground.

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A linear function modeling the height after t seconds has the following format:

[tex]h(t) = at + h(0)[/tex]

In which:

  • a is the slope, which is the rate of change of the height.
  • h(0) is the initial height.

  • The acorn is falling from 13 feet, thus [tex]h(0) = 13[/tex]
  • It descends at a rate of 4.8 feet every second, thus the slope is negative, that is, [tex]a = -4.8[/tex]
  • The equation for the height after t seconds is:

[tex]h(t) = -4.8t + 13[/tex]

  • The acorn is 1 foot above ground when: [tex]h(t) = 1[/tex]

Thus:

[tex]h(t) = -4.8t + 13[/tex]

[tex]1 = -4.8t + 13[/tex]

[tex]-4.8t + 13 = 1[/tex]

[tex]4.8t = 12[/tex]

[tex]t = \frac{12}{4.8}[/tex]

[tex]t = 2.5[/tex]

It takes 2.5 seconds for the acorn to be 1 foot above the ground.

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