Answer:
[tex] \frac{1}{8} \: and \: \frac{2}{3} [/tex]
[tex] \frac{1 \times 3}{24} and \: \frac{16}{24} [/tex]
[tex] \frac{3}{24} + \frac{16}{24} = \frac{19}{24} [/tex]
[tex] \frac{24}{24} - \frac{19}{24} = \frac{5}{24} [/tex]
5/24 this is his leftovers