Answer:
The time taken will be "1 hour 51 min". The further explanation is given below.
Explanation:
The given values are:
Number of required layers:
= [tex]\frac{38}{0.25}[/tex]
= [tex]152 \ layers[/tex]
Diameter (d):
= 1.25 mm
Velocity (v):
= 40 mm/s
Now,
The area of one layer will be:
= [tex]38\times 38 \ mm^2[/tex]
= [tex]1444 \ mm^2[/tex]
The area covered every \second will be:
= [tex]d\times v[/tex]
= [tex]1.25\times 40[/tex]
= [tex]50 \ mm^2[/tex]
The time required to deposit one layer will be:
= [tex]\frac{1444}{50}[/tex]
= [tex]28.88 \ sec[/tex]
The time required for one layer will be:
= [tex]15 \ sec[/tex]
∴ Total times required for one layer will be:
= [tex]15+28.88[/tex]
= [tex]43.88 \ sec[/tex]
So,
Number of layers = 152
Therefore,
Total time will be:
= [tex]152\times 43.88[/tex]
= [tex]6669.76 \ sec[/tex]
= [tex]1 \ hour \ 51 \ min[/tex]
Given values are:
Now,
Area of one layer will be:
= [tex]38\times 38[/tex]
= [tex]1444 \ mm^2[/tex]
Area covered per second:
= [tex]d\times v[/tex]
= [tex]1.25\times 40[/tex]
= [tex]50 \ mm^2[/tex]
= [tex]\frac{1444}{50}[/tex]
= [tex]28.88 \ sec[/tex]
= [tex]15 \ sec[/tex]
∴ Total time for 1 layer will be:
= [tex]15+28.88[/tex]
= [tex]43.88 \ sec[/tex]
hence,
The total time required:
= [tex]152\times 43.88[/tex]
= [tex]6669.76 \ sec[/tex]
= [tex]1 \ hour \ 51 \ minutes[/tex]
Thus the above response is right.
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