Answer:
The acceleration of the car is 0.244 m/s²
Explanation:
Given;
mass of the car, m = 2,000 kg
applied parallel force on the car, F = 560 N
mass of the two passengers, m = 2 x 55 kg = 110 kg
frictional force on the car (reducing horizontal motion), Fk = 45 N
Weight of the car acting downward, W = 2,000 x 9.8 = 19,600 N
weight of the two passengers acting downward, w = 110 x 9.8 = 1078 N
The net horizontal force on the car is given by;
∑Fx = F - Fk
∑Fx = 560 - 45
∑Fx = 515 N
Apply Newton's second law of motion;
F = ma
where;
m is the total mass of the system = mass of car + mass of passengers
m = 2000 + 110 = 2,110 kg
a = ∑Fx / m
a = 515 / 2110
a = 0.244 m/s²
Therefore, the acceleration of the car is 0.244 m/s²
