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a blackbody is at temperature of 500°C . What would be its temperature in Kelvin for it to radiate twice as much energy per second?​

Respuesta :

okpalawalter8

Answer:

  • Its temperature in Kelvin for it to radiate twice as much energy = [tex]919.257k[/tex]

Explanation:

Energy = [tex]6AT^4[/tex]

therefore,

[tex]\frac{E_1}{E_2} = \frac{T_1^4}{T_2^4}[/tex]

where [tex]E_2 = 2E_1[/tex]

therefore,

[tex]\frac{E_1}{2E_1} = \frac{(500+273)^4}{T_2^4}\\\\T_2 = 919.257k\\\\T_2 = 646.257^oC[/tex]

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