Complete Question
A parallel plate capacitor contains a positively charged plate on the left, and a negatively charged plate on the right. An electron in between the plates is moving to the right. Which statement is true?
Group of answer choices
a The potential energy of the electron is decreasing and it is moving to a region having a higher potential
b The potential energy of the electron is decreasing and it is moving to a region having a lower potential.
c The potential energy of the electron is increasing and it is moving to a region having a lower potential
d The potential energy of the electron is increasing and it is moving to a region having a higher potential.
Answer:
The correct option is C
Explanation:
From the question we are told that
An electron in between the plates is moving to the right
Generally the potential energy of the electron is mathematically represented as
[tex]PE = e * V[/tex]
Here e is the charge on the electron and V is the electric potential of the electron
Generally the left side with the positive charge has a higher potential than the right side with the negative charge
Now when the potential energy of the electron increases it will move toward the plate with the lower potential which is the left plate
