Answer:
[tex]\boxed {\boxed {\sf D. \ -11 \ m/s^2}}[/tex]
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
[tex]a=\frac{v_f-v_i}{t}[/tex]
where Vf is the final velocity, Vi is the initial velocity, and t is the time.
Since the car came to a complete stop, it's final velocity was 0 meters per second.
The initial velocity was 22 meters per second.
The time was 2.0 seconds.
[tex]v_f=0 \ m/s\\v_i=22 \ m/s\\t= 2.0 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{0 \ m/s-22 \ m/s}{ 2.0 \s }[/tex]
Subtract in the numerator first.
[tex]a=\frac{-22 \ m/s}{2.0 \ s}[/tex]
Divide.
[tex]a= -11 \ m/s^2[/tex]
The acceleration of the car was -11 meters per square second. The negative acceleration indicates slowing down/stopping.
