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Triangle GHJ with vertices G(-2,4), H(3,6), and J(3,-2) is dilated by a factor of centered at the origin. What are the coordinates of G' after the dilation? 63,4) (2,4) . 3) O 12 2 3 3 3 (3,-4)​

Triangle GHJ with vertices G24 H36 and J32 is dilated by a factor of centered at the origin What are the coordinates of G after the dilation 634 24 3 O 12 2 3 3 class=

Respuesta :

Emma3ichhol29

Answer:

The answer would most likely be the second one because that one makes the most sense here.

Step-by-step explanation:

MrRoyal

When a triangle is dilated, the size of the triangle changes.

The coordinate of G' after dilation is: (a) [tex]\mathbf{(-\frac 23,\frac 43)}[/tex]

The vertices are given as:

[tex]\mathbf{G = (-2,4)}[/tex]

[tex]\mathbf{H = (3,6)}[/tex]

[tex]\mathbf{J = (3,-2)}[/tex]

The scale factor (k) is given as:

[tex]\mathbf{k =\frac 13}[/tex]

So, the image of G is calculated as:

[tex]\mathbf{G' = k \times G}[/tex]

This gives:

[tex]\mathbf{G' = \frac 13 \times (-2,4)}[/tex]

[tex]\mathbf{G' = (-\frac 23,\frac 43)}[/tex]

Hence, the coordinate of G' after dilation is: (a) [tex]\mathbf{(-\frac 23,\frac 43)}[/tex]

Read more about dilations at:

https://brainly.com/question/13176891

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