Answer:
1.7 m
Explanation:
[tex]v_x[/tex] = Velocity of ball in x direction = 4.47 m/s
[tex]u_y[/tex] = Velocity of ball in y direction = 0
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
t = Time taken
[tex]s_y[/tex] = Vertical displacement = 0.7 m
[tex]s_y=u_yt+\dfrac{1}{2}gt^2\\\Rightarrow 0.7=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{0.7\times 2}{9.81}}\\\Rightarrow t=0.38\ \text{s}[/tex]
Horizontal displacement is given by
[tex]s_x=v_xt\\\Rightarrow s_x=4.47\times 0.38\\\Rightarrow s_x=1.7\ \text{m}[/tex]
The passenger should throw the ball 1.7 m in front of the bucket.
