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Find the equation for a polynomial f(x) that satisfies the following:
•Degree 3
•Zero at 2=4
•Zero at 2 = 1
•Zero at x =2
•y-intercept of (0,4)

Find the equation for a polynomial fx that satisfies the following Degree 3 Zero at 24 Zero at 2 1 Zero at x 2 yintercept of 04 class=

Respuesta :

mhanifa

Answer:

  • f(x) = 1/2(4 - x)(x - 1)(x - 2)

Step-by-step explanation:

Considering zero's and a coefficient, the function is:

  • f(x) = a(x - 4)(x - 1)(x - 2)

Considering y-intercept:

  • f(0) = a(0 - 4)(0 - 1)(0 - 2)
  • 4 = a(-4)(-1)(-2)
  • 4 = -8a
  • a = -1/2

So the function is:

  • f(x) = -1/2(x - 4)(x - 1)(x - 2) = 1/2(4 - x)(x - 1)(x - 2)

The graph showing zero's is attached

Ver imagen mhanifa

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