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A box of mass 7.0 kg is accelerated from rest across a floor at a rate of 2.0 m/s2 for 9.0 s .Find the net work done on the box. Express your answer to two significant figures and include the appropriate units.

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samuelonum1

Answer:

Explanation:

Step one:

given data

mass = 7kg

acceleration =2m/s^2

time= 9seconds

acceleration = velocity/time

velocity= acceleration *time

velocity=2*9

velocity= 18m/s

distance moved= velocity* time

distance= 18*9

distance=162m

we also know that the force on impulse is given as

Ft=mv

F=mv/t

F=7*18/9

F=126/9

F=14N

work done = Force* distance

work done=14*162

work=2268Joules

work= 2.27kJ

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