Answer:
The constant charge for each minute used is $50
Step-by-step explanation:
In order to solve this problem we will need to set two variables up. In this case:
F = constant Fee
R = rate per minute used
So the cost for the month of January is calculated like this:
F+300R=68
and the cost for February is calculated like this:
F+275R=66.5
So no we have a system of equations we can solve simultaneously. This can be solved by using different methods, elimination, substitution, graphically or by using matrices. I will solve this by substitution.
So let's solve the first equation for R:
[tex]R=\frac{68-F}{300}[/tex]
and let's substitute this first equation into the second equation:
[tex]F+275(\frac{68-F}{300})=66.5[/tex]
and now we can solve this for F:
[tex]F+11(\frac{68-F}{12})=66.5[/tex]
We can multiply both sides by 12 so we get:
12F+11(68-F)=798
12F+748-11F=798
F= $50
