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A transformer has 90 turns in the primary coil and 9 turns in the secondary coil If the output voltage is 6 V, what is the input voltage

Respuesta :

pstnonsonjoku

Answer:

60 V

Explanation:

From;

Vs/Vp = Ns/Np

Where;

Vs = voltage in the secondary coil = 6V

Vp = voltage in the primary coil= ??

Ns = number of turns in the secondary coil = 9

Np= number of turns in the primary coil = 90

6/Vp = 9/90

Vp= 90 * 6/9

Vp=  60 V

Cricetus

The initial voltage will be "60 V".

Given:

  • Secondary coil's voltage, [tex]V_s = 6 \ V[/tex]
  • No. of turn in secondary coil, [tex]N_s = 9[/tex]
  • No. of turn in primary coil, [tex]N_p = 90[/tex]

As we know,

→ [tex]\frac{V_s}{V_p} = \frac{N_s}{N_p}[/tex]

or,

→ [tex]V_p = \frac{N_p\times V_s}{N_s}[/tex]

By substituting the values, we get

        [tex]= \frac{90\times 6}{9}[/tex]

        [tex]= \frac{300}{9}[/tex]

        [tex]= 60 \ V[/tex]      

Thus the above answer is  correct.

   

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