Answer:
[tex]\boxed{x = 4~~and~~y = -2}[/tex]
Step-by-step explanation:
3x + 5y = 2 (times 5) 15x + 25y = 10
5x + 8y = 4 (times 3) 15x + 24y = 12
.
15x + 25y = 10
15x + 24y = 12
y = -2
.
Substitute the value of y to one of equations
3x + 5y = 2
3x + 5(-2) = 2
3x - 10 = 2
3x = 2 + 10
3x = 12
[tex]x = \frac{12}{3}[/tex]
x = 4