Answer:
The distance between the two jets is approximately 2.947 kilometers.
Step-by-step explanation:
From the statement we know the location of each jet in polar coordinates, which are defined by the following notation:
[tex]\vec r = (r, \theta)[/tex] (1)
Where:
[tex]r[/tex] - Distance of the jet from the origin, measured in kilometers.
[tex]\theta[/tex] - Angle of the jet with respect to the east direction, measured in sexagesimal degrees.
To transform polar coordinates into rectangular coordinates, we use the following expressions:
[tex]x = r\cdot \cos \theta[/tex] (2)
[tex]y = r\cdot \sin \theta[/tex] (3)
And lastly, we determine the distance between the two jets ([tex]d[/tex]), measured in kilometers, by the Pythagorean Theorem:
[tex]d = \sqrt{(r_{2}\cdot \cos \theta_{2}-r_{1}\cdot \cos \theta_{1})^{2}+(r_{2}\cdot \sin \theta_{2}-r_{1}\cdot \sin \theta_{1})^{2}}[/tex] (4)
If we know that [tex]r_{2} = 4\,km[/tex], [tex]\theta_{2} = 150^{\circ}[/tex], [tex]r_{1} = 2\,km[/tex] and [tex]\theta_{1} = 195^{\circ}[/tex], the distance between the two jets is:
[tex]d = \sqrt{[(4\,km)\cdot \cos 150^{\circ} -(2\,km)\cdot \cos 195^{\circ}]^{2}+[(4\,km)\cdot \sin 150^{\circ} -(2\,km)\cdot \sin 195^{\circ}]^{2}}[/tex]
[tex]d \approx 2.947\,km[/tex]
The distance between the two jets is approximately 2.947 kilometers.
