Respuesta :

violet46

 y=4x^2+5x-6y=4x2+5x−6

:

Given points are :

  x     =    -2      0       4

y=f(x) =    0       -6      78

We have to model the parabola with the help of these points

Solution:

We consider a standard equation of parabola y= ax^2+bx+cy=ax2+bx+c

now, we put the points in the equation we get,

at (-2,0) is    4a-2b+c=0

at (0,-6) is    c=-6

at (4,78) is    78= 16a+4b+c  

now, solving these equation we get, a= 4    , b= 5    , c= -6

so the equation formed with these points is   y=4x^2+5x-6y=4x2+5x−6

we can see this in the graph attached.

Step-by-step explanation:

Hope this helps!! :D

curranms030238

Answer:

the answer to 14 is D

and 15 is i think x=  [tex]\frac{5+\sqrt{13} }{2}, \frac{5-\sqrt{13} }{2} \\[/tex]

Step-by-step explanation:

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