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The altitude of an airplane is decreasing at a rate of 42 ft per second what is the change in altitude of the airplane over a. Of 22 seconds

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Answer:

Over a 22 seconds, the altitude will be: 924 feet

Step-by-step explanation:

  • Let 'x' be the time in seconds
  • Let 'y' be the altitude

As the altitude of an airplane is decreasing at a rate of 42 ft per second.

Thus, the expression to find the altitude at x seconds is:

y = 42x

so at x = 1 sec, y = 42 feet

Now, putting x = 22 seconds to determine the altitude at 22 seconds

y = 42x

  = 42(22)

  = 924 feet

Thus, over a 22 seconds, the altitude will be: 924 feet

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