The ratio of H⁺ ions to OH⁻ ions at a pH = 2 is 10¹⁰
Given
ph = 2
Required
The concentration of H⁺ and OH⁻ ions
Solution
pH=-log[H⁺]
2=-log[H⁺]
[H⁺]=10⁻²
pH+pOH=14
pOH=14-2
pOH=12
pOH=-log[OH⁻]
12=-log[OH⁻]
[OH⁻]=10⁻¹²
[tex]\tt \dfrac{10^{-2}}{10^{-12}}=10^{10}[/tex]
Answer:
First one: 0.01
second one: 0.000000000001
third one: 10000000000