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Considering this balanced chemical equation, how many grams of HgO will be produced when 44 g of Hg react with excess O2?

2Hg (l) + O2 (g) --> 2HgO (s)

A 28 g
B 44 g
C 48 g
D 96 g

Also, how would you go to solve this problem? Thanks!

Respuesta :

drpelezo

Answer:

48g

Explanation:

2Hg(l) + O₂(g) => 2HgO

44g      excess        ?

44g/200.59g·mol⁻¹ = 0.219 mole Hg(l) = 0.219 mole HgO(s) produced.*

*Since coefficients are equal for Hg and HgO then the moles of HgO produced is the same as moles Hg used.

Convert 0.219 mole HgO to grams => 0.219mol x 216.95g/mol = 47.512g HgO ≅ 48g (2 sig figs)