Given that,
The given expression is : [tex]16x^0+2x^2{\cdot}y^{-1}[/tex]
To find,
The value of the above expression when x = 2 and y = 4
Solution,
We have,
[tex]16x^0+2x^2{\cdot}y^{-1}[/tex]
Put x = 2 and y = 4 in the above expression.
[tex]16x^0+2x^2{\cdot}y^{-1}\\\\=16\times (2)^0+2(2)^2\times (4)^{-1}\\\\=16\times 1+2(2)^2\times\dfrac{1}{4}\\\\=16+2\\\\=18[/tex]
So, the value of the above expression is 18.