Answer:
c, 280,000J
Explanation:
You should use the equation KE (Kinetic Energy) = [tex]\frac{1}{2} mv^2[/tex]
m = 2500
v = 15
KE = [tex]\frac{1}{2} * 2500 * (15)^2\\[/tex]
KE = 281250 Joules.
This is consistent with the answer B, as all of the parameters given to you are rounded to 2 significant figures so naturally, the answer should also be rounded to 2 sig figs.
KE = 280,000 J
