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Fill in the blanks. After conducting research around the country, Ford Motor Company determined that the probability of a randomly selected Ford vehicle on the road being driven by a female is 0.71. If there are 3,682 Ford vehicles in your town, around __________ cars will be driven by females, give or take __________. Assume each car represents an independent tria

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Answer:

2614 cars will be driven by females, give or take 28.

Step-by-step explanation:

For each Ford vehicle, there are only two possible outcomes. Either it is driven by a female, or it is not. Cars are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Company determined that the probability of a randomly selected Ford vehicle on the road being driven by a female is 0.71.

This means that [tex]p = 0.71[/tex]

If there are 3,682 Ford vehicles in your town

This means that [tex]n = 3682[/tex]

__________ cars will be driven by females, give or take __________.

The mean and the standard deviation complete this. So

Mean: [tex]E(X) = np = 3682*0.71 = 2614[/tex]

Standard deviation: [tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{3682*0.71*0.29} = 28[/tex]

2614 cars will be driven by females, give or take 28.