cburrell60212 cburrell60212

09-02-2021
Chemistry

contestada

If 0.813 g of O3 reacts with 0.605 g of NO, how many grams of NO2 will be produced?

Respuesta :

savsammy127 savsammy127

09-02-2021

Answer:

0.74 g O

3

=

48

0.74

=0.0154 mol O

3

0.67 g NO=

30

0.67

=0.0223 mol NO

O

3

is the limiting reagent and NO is in excess =0.0223−0.0154=0.007 mol

Thus, O

3

taken =NO

2

formed =0.0154 mol NO

2

=0.0154×46 g NO

2

Explanation:

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