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The position of a particle on a straight line is given by s(t) = 3 – cos(t).
A. Find velocity and acceleration at t = 4.3 s.
Round your answers to 2 decimal(s).
v(t) =
a(t) =

The position of a particle on a straight line is given by st 3 cost A Find velocity and acceleration at t 43 s Round your answers to 2 decimals vt at class=

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LammettHash

Given the position function

s(t) = 3 - cos(t )

differentiate once to get the velocity, and twice to get the acceleration:

v(t) = s'(t) = sin(t )   →   v (4.3 s) ≈ -0.92

a(t) = s''(t) = v'(t) = cos(t )   →   a (4.3 s) ≈ -0.40

The acceleration is negative, so the particle is slowing down.

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