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Consider the equation 4•e^2.7x = 33

Solve the equation for x. Express the solution as a logarithm in base-e.
x ≈

Approximate the value of x. Round your answer to the nearest thousandth.
x≈

Consider the equation 4e27x 33 Solve the equation for x Express the solution as a logarithm in basee x Approximate the value of x Round your answer to the neare class=

Respuesta :

Answer:

[tex] \huge x = ln( \frac{33}{4} ) \times \frac{ 10}{27} \\ \huge \: x \approx 0.782[/tex]

Step-by-step explanation:

to understand this

you need to know about:

  • logarithm
  • PEMDAS

let's solve:

[tex]4 {e}^{2.7x} = 33 \\ {e}^{2.7x} = \frac{33}{4} \\ 2.7x = ln( \frac{33}{4} ) \\ x = ln( \frac{33}{4} ) \times \frac{ 10}{27} \\ x \approx 0.782[/tex]

An equation is formed of two equal expressions. The value of x is 0.7815.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The equation 4•e^2.7x = 33 can be solved for x as,

[tex]4\cdot e^{2.7x }= 33\\\\ e^{2.7x }= \dfrac{33}{4}\\\\\text{Taking anti-log}\\\\2.7x = ln\frac{33}{4}\\\\x = ln(\dfrac{33}{4}) \times \dfrac{1}{2.7}\\\\x=0.7815[/tex]

Hence, the value of x is 0.7815.

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