Answer:
PR= 8
ST=5
Step-by-step explanation:
PQ and PR are congruent so
2x=8
x=4
2*4=8
PR=8
ST and TU are congruent so
5z=2z+3
3z=3
z=1
5*1=5
PR
QS=SR (marked)
a²=b²+c² (TRIANGLE PQS)
PQ²=PS²+QS²
8²=PS²+SR² (PQ=8, QS=SR)
64=PS²+SR²
a²=b²+c² (TRIANGLE PRS)
PR²=PS²+SR²
(2x)²=64
PR=2x=2(4)=8
ST
a²=b²+c² (TRIANGLE VUT)
VT²=TU²+UV²
VT²=(2z+3)²+UV²
VT²=4z²+12z+9+UV²
a²=b²+c² (TRIANGLE VST)
VT²=VS²+ST²
VT²=VS²+25z²
4z²+12z+9+UV²=VS²+25z²
21z²-12z-9=0
7z²-4-3=0
(7z+3)(z-1)=0
z=-3/7 or z=1
cant be neg, z=1
ST=5(1)=5
