Respuesta :

[tex]\bf{ \underline{Given:- }}[/tex]

[tex] \sf{• \: Power \: (P) = 60 \: w}[/tex]

[tex] \sf{• \: Resistance \: (R) = 880 \: Ω}[/tex]

[tex] \\ [/tex]

[tex]\bf{ \underline{To \:  Find :- }}[/tex]

[tex] \sf• \: The \: Current \: (I).[/tex]

[tex] \\ [/tex]

[tex] \huge\bf{ \underline{ Solution :- }}[/tex]

[tex] \sf We \: know \: that,[/tex]

[tex] \bf \red {\bigstar{ \: P = I^{2} R}}[/tex]

[tex] \rightarrow \sf 60 = I^{2} \times 880[/tex]

[tex] \rightarrow \sf \frac{60}{880} = I^{2} [/tex]

[tex] \rightarrow \sf I^{2} = 0.0681[/tex]

[tex] \rightarrow \sf I = \sqrt{0.0681}[/tex]

[tex] \rightarrow \sf I = 0.261 \: \: (approx.)[/tex]

[tex] \\ [/tex]

[tex]\bf The \: \: value \: \: of \: \: I \: \: is \: \: 0.261 \: \: Amps. \: \: (approx.)[/tex]