Dgrk
contestada

In the game “Sandwich” three cards are dealt from a 52-card deck. To win, the value of the third card must be between the first two cards. What is the probability of winning given the first two cards dealt are a 6 and a 10?

Show ALL work!!!

Respuesta :

Answer:

[tex]\frac{3}{13} ,\frac{12}{52}[/tex]

Step-by-step explanation:

In a 52 card deck there a 4 of ech individual card

There are 3 card values between 6 and 10, (7,8,9)

[tex](3)(4)=12[/tex]

12 out of the 52 cards could win the game, so there is a probability of

[tex]\frac{12}{52}[/tex]  [tex]or[/tex] [tex]\frac{3}{13}[/tex]

plz mark me brainliest. :)