Answer:
24.5 s
Explanation:
We can calculate time of flight of a projectile using below formula
T = (2Usinθ)/g
g = acceleration due to gravity= 9.81 m/s^2
U = initial velocity= 200 m/s,
θ = horizontal angle of projection= 37°
Sin(37°)= 0.60
If we input the values above, we have
=(2× 400×0.60)/9.81
= 480/9.81
T = 24.5 s
Hence, it takes 24.5 s before the projectile it returns to its original elevation at C
