Brainly777
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Write a number in each box to make an equation that has exactly one real solution.

3(2a+1)-a = __a + __a

using the numbers 1 - 10

Write a number in each box to make an equation that has exactly one real solution 32a1a a a using the numbers 1 10 class=

Respuesta :

Blurryface25
3(2a+1)-a
6a+1-a→→ 6a-a equals 5a
5a+3
the number in the first box is 5 and the second box 3

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