Answer:
the internal resistance of the cell is 0.1 ohm.
Explanation:
Given;
p.d at the terminals of a battery at no load, E₁ = 25 V
p.d at the terminals of a battery at a load, E₂ = 24 V
current through the circuit, I = 10 A
The potential drop across the circuit, V = E₁ - E₂
= 25 V - 24 V
= 1 V
The internal resistance of the cell is calculated as follows;
r = V/I
r = 1 / 10
r = 0.1 ohm
Therefore, the internal resistance of the cell is 0.1 ohm.
