egarcia1
contestada

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

Respuesta :

(-3, 11)+(1, -3)=(-2, 8)
mozarth11
Determinante:
x....y....1
-3..11...1
1...-3....1

11x+y+9+3x+3y-11 = 0
11x+3x+y+3y+9-11 = 0
14x+4y-2 = 0

4y = -14x + 2
y = (-14x + 2)/4
y = (-7x+1)/2

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