Answer:
111.03kPa = P₂
Explanation:
Gay Lussac's Law states that the pressure of a gas is directly proportional to the absolute temperature when volume remains constant.
The equation is:
P₁T₂ = P₂T₁
Where P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas.
P₁ = 85.5kPa
T₂ = 127°C + 273.15 = 400.15K
P₂ = ?
T₁ = 35°C + 273.15 = 308.15K
P₁T₂ = P₂T₁
85.5kPa*400.15K = P₂*308.15K
111.03kPa = P₂
