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Br2 + 2LiF → 2LiBr + F2
Given: If 3.6 moles of Br2, react with 9.4 moles of LiF
a) How many moles of F, are produced? I​

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1 grams F2 to mol = 0.02632 mol

10 grams F2 to mol = 0.26318 mol

20 grams F2 to mol = 0.52636 mol

30 grams F2 to mol = 0.78954 mol

40 grams F2 to mol = 1.05272 mol

50 grams F2 to mol = 1.3159 mol

100 grams F2 to mol = 2.6318 mol

200 grams F2 to mol = 5.2636 mol

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