Answer:
See solutions below
Step-by-step explanation:
Match the range of the function f(x)=x^2+2x-1 to its domain
Domains of the function are the input values x i.e 2, -2, 3 and 3
corresponding f(x) for each values are the range
when x = 2
f(2)=2^2+2(2)-1
f(2) = 4 + 4 - 1
f(2) = 7
when x = -2
f(-2)=(-2)^2+2(-2)-1
f(-2) = 4 - 4 - 1
f(-2) = -1
when x = 3
f(3)=3^2+2(3)-1
f(3) = 9 + 6 - 1
f(3) = 14
when x = -3
f(-3)=(-3)^2+2(-3)-1
f(-3) = 9 -6 - 1
f(-3) = 2
