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A young boy swings a yo-yo horizontally above his head so that the yo-yo has a centripetal acceleration of 200 m/s^2. If the yo-up’s string is 0.33 m long, what is the yo-up’s tangential speed?

Respuesta :

hamzaahmeds

Answer:

v = 8.12 m/s

Explanation:

The centripetal acceleration of the yo-yo is given by the following formula:

[tex]a_c = \frac{v^2}{r}\\\\v^2 = a_cr\\v = \sqrt{a_cr}[/tex]

where,

v = tangential speed = ?

ac = centripetal acceleration = 200 m/s²

r = radius = length of string = 0.33 m

Therefore, using the given values in the formula, we get:

[tex]v = \sqrt{(200\ m/^2)(0.33\ m)}[/tex]

v = 8.12 m/s