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A circle with a radius of 1 in. is inscribed in a right triangle with legs of 3 in. and 4 in. If a point is randomly chosen within the triangle, what is the probability that the point is NOT also in the circle?​

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aminerassam

Answer:

P = (6-π)/6

Explanation:

Circle Area:

CA = 1²×π

CA ≈ π in²

Triangle Area:

TA = 3×4/2 = 6 in²

Probability:

P(point not in circle) = (6-π)/6 ≈ 0.48 ≈ 47.64%

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