Answer:
5832 mosquitoes
Step-by-step explanation:
As we know
[tex]A = A_0 * e^{kt}\\[/tex]
Where A is the population after t days
A0 is the initial population
k is rate constant and
t is the time in days
Substituting the given values we get
[tex]1900 = 1000 * e^{1 * k}\\1.9 = e^{1 * k}\\k = 0.587[/tex]
Size of colony after 4 days
[tex]A = 1000 * e^ {(0.587*4)}\\A = 5832[/tex]mosquitoes
